How do you simplify $(7-2i)(6-4i)$ ?

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Answer 1 · 2018-05-26T13:23:55

$34-40i$

We define the product of two complex numbers $a+bi$ and $c+di$ as

$(a+bi)(c+di):=(ac-bd)+(ad+bc)i$

So

$(7-2i)(6-4i)=(42-8)+(-28-12)i=34-40i$

How do you simplify (7-2i)(6-4i)(7-2i)(6-4i)?