# How do you simplify (7d^-6)(-4d^-2)?

Sep 24, 2015

$- \frac{28}{d} ^ 8$

#### Explanation:

To multiply ${d}^{-} 6$ and ${d}^{-} 2$, you only have to add their exponents together (Law of Indices). Also, to remove the negative sign from the exponent, you simply have to get the reciprocal of the base.

(7d^(−6))(−4d^(−2))

=(7)*(-4)⋅(d^(-6+(-2)))

$= \left(- 28\right) \cdot \left({d}^{-} 8\right)$

$= \left(- 28\right) \cdot \left(\frac{1}{d} ^ 8\right)$

$= \textcolor{b l u e}{- \frac{28}{d} ^ 8}$