How do you simplify #cos(sin^-1(3/5)-cos^-1(1/2))#?

1 Answer
May 13, 2016

#(1/10)(+-4+-3sqrt3)#

Explanation:

Let #a = sin^(-1)(3/5) and b = cos ^(-1)(1/2)#.

Then, # sin a = 3/5, cos a = +-4/5, cos b = 1/2 and sin b = +-sqrt3 /2#

Now, the given expression is #cos (a - b )#

#= cos a cos b + sin a sinb#

#=+-2/5+-3sqrt3/10=(1/10)(+-4+-3sqrt3)#.

The choice of sign depends on the specified ranges (if any ), for the inverse angles.a and b.