# How do you simplify  sqrt128?

Feb 23, 2016

I found: $8 \sqrt{2}$

#### Explanation:

I would try by writing $128$ in a different way:

$128 = 4 \cdot 4 \cdot 4 \cdot 2$

so our root becomes:

$\sqrt{4 \cdot 4 \cdot 4 \cdot 2} = \sqrt{4} \cdot \sqrt{4} \cdot \sqrt{4} \cdot \sqrt{2}$

we know that $\sqrt{4} = 2$, so:

$\sqrt{128} = 2 \cdot 2 \cdot 2 \cdot \sqrt{2} = 8 \sqrt{2}$