# How do you simplify the expression arctan(1/sqrt3)?

$\frac{\pi}{6.}$
Let $\arctan \left(\frac{1}{\sqrt{3}}\right) = \theta$
Then, by defn., $\tan \theta = \frac{1}{\sqrt{3}} = \tan \left(\frac{\pi}{6}\right) ,$ where, $\theta \in \left(- \frac{\pi}{2} , \frac{\pi}{2}\right)$
$\therefore \theta = \arctan \left(\frac{1}{\sqrt{3}}\right) = \frac{\pi}{6.}$