Question

How do you simplify the expression `arctan(1/sqrt3)`?

Answer 1

`pi/6.`

Explanation:

Let `arctan(1/sqrt3)=theta`

Then, by defn., `tantheta=1/sqrt3=tan(pi/6),` where, `theta in (-pi/2,pi/2)`
`:. theta=arctan(1/sqrt3)=pi/6.`