How do you simplify the product (3y + 7)(4y + 5) and write it in standard form?

Jan 30, 2016

$12 {y}^{2} + 43 y + 35$

Explanation:

Each term in the 2nd bracket must be multiplied by each term

in the 1st bracket,

The way to do this is 3y (4y + 5 ) + 7 (4y + 5 )

$= 12 {y}^{2} + 15 y + 28 y + 35$

simplifying to : $12 {y}^{2} + 43 y + 35$