How do you simplify # (x+3)(x-4)#? Algebra Polynomials and Factoring Multiplication of Polynomials by Binomials 1 Answer Shwetank Mauria Jul 7, 2016 #(x+3)(x-4)=x^2-x-12# Explanation: #(x+3)(x-4)# = #x(x-4)+3(x-4)# = #x^2-4x+3x-12# = #x^2-x-12# Answer link Related questions What is FOIL? How do you use the distributive property when you multiply polynomials? How do you multiply #(x-2)(x+3)#? How do you simplify #(-4xy)(2x^4 yz^3 -y^4 z^9)#? How do you multiply #(3m+1)(m-4)(m+5)#? How do you find the volume of a prism if the width is x, height is #2x-1# and the length if #3x+4#? How do you multiply #(a^2+2)(3a^2-4)#? How do you simplify #(x – 8)(x + 5)#? How do you simplify #(p-1)^2#? How do you simplify #(3x+2y)^2#? See all questions in Multiplication of Polynomials by Binomials Impact of this question 2127 views around the world You can reuse this answer Creative Commons License