# How do you sketch the curve with parametric equations x = sin(t), y=sin^2(t) ?

Since we know that $- 1 \le \sin t \le 1$, the curve is limited to $- 1 \le x \le 1$.
By plugging $x = \sin t$ into $y = {\sin}^{2} t$, we have
$y = {\left(\sin t\right)}^{2} = {x}^{2}$.
Hence, the curve is the portion of the parabola $y = {x}^{2}$ between $x = - 1$ and $x = 1$, which looks like this: