How do you solve #-0.25(4v-8)=0.5(4-2v)#? Algebra Linear Equations Equations with Variables on Both Sides 1 Answer Kalyanam S. May 23, 2018 As below. Explanation: #-0.25 (4v - 8) = 0.5 (4 - 2v)# Using PEMDAS rule, #-0.25 * 4v + 0.25 * 8 = 0.5*4 - 0.5*2v#, removing bracelets. #-v + 2 = 2 - v#, multiplying. #cancel(-v )+cancel (v )=cancel( 2) - cancel(2)#, like terms together. #0# Answer link Related questions How do you check solutions to equations with variables on both sides? How do you solve #125+20w-20w=43+37w-20w#? How do you solve for x in #3(x-1) = 2 (x+3)#? Is there a way to solve for x without using distribution in #4(x-1) = 2 (x+3)#? How do you solve for t in #2/7(t+2/3)=1/5(t-2/3)#? How do you solve #5n + 34 = −2(1 − 7n)#? How do you simplify first and then solve #−(1 + 7x) − 6(−7 − x) = 36#? Why is the solution to this equation #-15y + 7y + 1 = 3 - 8y#, "no solution"? How do you solve for variable w in the equation #v=lwh#? How do you solve #y-y_1=m(x-x_1)# for m? See all questions in Equations with Variables on Both Sides Impact of this question 1832 views around the world You can reuse this answer Creative Commons License