# How do you solve 1/2(10x+7)=5x?

If $\frac{1}{2} \left(10 x + 7\right) = 5 x$
$\textcolor{w h i t e}{\text{XXX}} {\cancel{5 x}}^{0} + \frac{7}{2} = {\cancel{5 x}}^{0}$
$\textcolor{w h i t e}{\text{XXX}} \frac{7}{2} = 0$ which is impossible.