# How do you solve 10 + x - 2x^2<0?

We first rewrite this in standard form: $- 2 {x}^{2} + x + 10 < 0$
$y = 0$ gives us $x = 2.5 \mathmr{and} x = - 2$
$x < - 2 \mathmr{and} x > 2.5$