How do you solve # 10 + x - 2x^2 <0#? c) #-2 + 7x - 3x^2<0#

1 Answer
Jan 21, 2016

Answer:

graph{2x^2-x-10 [-10, 10, -5, 5]} 2x-5)(x+2)<0 # Thus per the inequality the true set include only
The left hand side of the quadratic less that zero, i.e. -2

Explanation:

Multiply the entire equation by -1 and find it factors (true set):
#10+x-2x^2 = 2x^2-x-10<0#
#(2x-5)(x+2)<0 # Thus per the inequality the true set include only
The left hand side of the quadratic less that zero, i.e. -2
look at the graph for clarity.
you should try the 2nd problem yourself usin the same approach and rational I provided you here