Question

How do you solve `10A=60-2A`?

Answer 1

`A = 5`

Explanation:

First, isolate the `A` terms on the left side of the equation and the constants on the right side of the equation while keeping the equation balanced:

`10A + color(red)(2A) = 60 - 2A + color(red)(2A)`

`(10 + 2)A = 60 - 0`

`12A = 60`

Now we can solve for `A` by dividing each side of the equation by `color(red)(12)` which will also keep the equation balanced:

`(12A)/color(red)(12) = 60/color(red)(12)`

`(color(red)(cancel(color(black)(12)))A)/cancel(color(red)(12)) = 5`

`A = 5`