# How do you solve 10A=60-2A?

Dec 23, 2016

$A = 5$

#### Explanation:

First, isolate the $A$ terms on the left side of the equation and the constants on the right side of the equation while keeping the equation balanced:

$10 A + \textcolor{red}{2 A} = 60 - 2 A + \textcolor{red}{2 A}$

$\left(10 + 2\right) A = 60 - 0$

$12 A = 60$

Now we can solve for $A$ by dividing each side of the equation by $\textcolor{red}{12}$ which will also keep the equation balanced:

$\frac{12 A}{\textcolor{red}{12}} = \frac{60}{\textcolor{red}{12}}$

$\frac{\textcolor{red}{\cancel{\textcolor{b l a c k}{12}}} A}{\cancel{\textcolor{red}{12}}} = 5$

$A = 5$