How do you solve #10t + 3=8t + 11#? Algebra Linear Equations Equations with Variables on Both Sides 1 Answer Lawson S. · Stefan V. Apr 9, 2018 #t = 4# Explanation: #10t + 3 = 8t +11# Subtract three from both sides #10t = 8t + 8 # Now subtract #8t# so that you can get all of your variables to one side. #(10t - 8t) = 2t# #2t=8# Now we will divide both sides by #2#. We do this so that we can get #t# by itself. #t = 4# Final Answer. Answer link Related questions How do you check solutions to equations with variables on both sides? How do you solve #125+20w-20w=43+37w-20w#? How do you solve for x in #3(x-1) = 2 (x+3)#? Is there a way to solve for x without using distribution in #4(x-1) = 2 (x+3)#? How do you solve for t in #2/7(t+2/3)=1/5(t-2/3)#? How do you solve #5n + 34 = −2(1 − 7n)#? How do you simplify first and then solve #−(1 + 7x) − 6(−7 − x) = 36#? Why is the solution to this equation #-15y + 7y + 1 = 3 - 8y#, "no solution"? How do you solve for variable w in the equation #v=lwh#? How do you solve #y-y_1=m(x-x_1)# for m? See all questions in Equations with Variables on Both Sides Impact of this question 808 views around the world You can reuse this answer Creative Commons License