# How do you solve 10x^2 + 19x + 6 = 0 by factoring?

$10 {x}^{2} + 19 x + 6 = 0 \implies 10 {x}^{2} + 4 x + 15 x + 6 = 0 \implies 2 x \left(5 x + 2\right) + 3 \left(5 x + 2\right) = 0 \implies \left(2 x + 3\right) \cdot \left(5 x + 2\right) = 0 \implies x = - \frac{3}{2} \mathmr{and} x = - \frac{2}{5}$