# How do you solve 11n - 3= 9n + 3?

Apr 11, 2017

See the entire solution process below:

#### Explanation:

First, add $\textcolor{red}{3}$ and subtract $\textcolor{b l u e}{9 n}$ from each side of the equation to isolate the $n$ term while keeping the equation balanced:

$11 n - 3 + \textcolor{red}{3} - \textcolor{b l u e}{9 n} = 9 n + 3 + \textcolor{red}{3} - \textcolor{b l u e}{9 n}$

$11 n - \textcolor{b l u e}{9 n} - 3 + \textcolor{red}{3} = 9 n - \textcolor{b l u e}{9 n} + 3 + \textcolor{red}{3}$

$\left(11 - \textcolor{b l u e}{9}\right) n - 0 = 0 + 6$

$2 n = 6$

Now, divide each side of the equation by $\textcolor{red}{2}$ to solve for $n$ while keeping the equation balanced:

$\frac{2 n}{\textcolor{red}{2}} = \frac{6}{\textcolor{red}{2}}$

$\frac{\textcolor{red}{\cancel{\textcolor{b l a c k}{2}}} n}{\cancel{\textcolor{red}{2}}} = 3$

$n = 3$