How do you solve #12+5v=2v-9#?

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Answer 1 · 2017-07-03T16:20:32

See a solution process below:

First, subtract #color(red)(12)# and #color(blue)(2v)# from each side of the equation to isolate the #v# term while keeping the equation balanced:

#12 + 5v - color(red)(12) - color(blue)(2v) = 2v - 9 - color(red)(12) - color(blue)(2v)#

#12 - color(red)(12) + 5v - color(blue)(2v) = 2v - color(blue)(2v) - 9 - color(red)(12)#

#0 + (5 - color(blue)(2))v = 0 - 21#

#3v = -21#

Now, divide each side of the equation by #color(red)(3)# to solve for #y# while keeping the equation balanced:

#(3v)/color(red)(3) = -21/color(red)(3)#

#(color(red)(cancel(color(black)(3)))v)/cancel(color(red)(3)) = -7#

#v = -7#