How do you solve $12 x + 3 = 6 x + 3$ $12x + 3 = 6x + 3$ ?

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Answer 1 · 2018-03-31T13:38:07

$x = 0$ $x=0$

Push all the variables to one side and constants to the other.

We get $12 x - 6 x = 3 - 3$ $12x-6x=3-3$

$6 x = 0$ $6x=0$

So, $x = 0$ $x=0$

Answer 2 · 2018-03-31T13:45:09

$x = 0$ $color(magenta)(x=0$

$12 x + 3 = 6 x + 3$ $12x+3=6x+3$

$12 x - 6 x = 3 - 3$ $12x-6x=3-3$

$6 x = 0$ $6x=0$

$x = \frac{0}{6}$ $x=0/6$

$x = 0$ $color(magenta)(x=0$

As a check:

$12 x + 3 = 6 x + 3$ $12x+3=6x+3$

$12 (0) + 3 = 6 (0) + 3$ $12(0)+3=6(0)+3$

$0 + 3 = 0 + 3$ $0+3=0+3$

$3 = 3$ $color(red)(3=3$

Hence it is proved that $x = 0$ $x=0$

~Hope this helps! :)

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