# How do you solve #12x – 5x < 6(x + 7)#?

##### 2 Answers

May 3, 2018

#### Explanation:

#"simplify left side and distribute parenthesis"#

#rArr7x<6x+42larrcolor(blue)"subtract 6x from both sides"#

#rArrx<42" is the solution"#

#x in(-oo,42)larrcolor(blue)"in interval notation"#

May 3, 2018

You get

#### Explanation:

I would simplify the left side, since

Therefore

Now

Therefore we have

So 7 of something should be smaller than 6 of something pluss 42.

I hope it then is easy to see that this is fulfilled if 1 of that something is smaller than 42,

i.e.

Normally we would do it this way, deducting the same amount from each side:

Which would give