# How do you solve 18-2(3m-1)=(6+2(m+3))/2?

Jun 30, 2017

$m = 2$

#### Explanation:

Start by simplifying both left and right sides:

$18 - 2 \left(3 m - 1\right) = \frac{6 + 2 \left(m + 3\right)}{2}$

$18 - 6 m + 2 = \frac{6 + 2 m + 6}{2}$

$20 - 6 m = \frac{12 + 2 m}{2}$

$20 - 6 m = 6 + m$

Bring the variable to one side by subtracting $m$ to both sides while also subtracting $20$ to both sides to isolate the variable.

$\cancel{20 - 20} - 6 m - m = 6 + \cancel{m - m} - 20$

$- 7 m = - 14$

Solve for $m$ by dividing $- 7$ from both sides:

$\frac{\cancel{- 7}}{\cancel{- 7}} m = \frac{- 14}{-} 7$

$m = 2$