How do you solve #2(2-3x)=4(1-3/2x)#?

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Answer 1 · 2016-12-30T20:46:23

#x# can have any value.

#2(2-3x)=4(1-3/2x)" "larr# remove the brackets

#4-6x=4-6x" "larr# both sides are identical

#6x-6x = 4-4#

#0=0#

This is a true statement but there is no #x# left to solve for.

This is a special type of equation called an identity.

It will be true for any and every value of #x#