How do you solve #2/3n+6=1/4n-3#?

1 Answer
Ratnaker Mehta
Jul 12, 2016

The soln. is #n=-108/5=-21.6#.

Explanation:

Given that, #2/3n+6=1/4n-3.#

Isolating the terms with variable #n# on #L.H.S.# and the consts. on the #R.H.S.#, we get,

#2/3n-1/4n=-6-3=-9.#

To get rid of fractions, we multiply the eqn. by #12#, which is the #l.c.m.# of nos. in Drs. of #L.H.S.#

#8n-3n=-108 rArr 5n=-108 rArr n=-108/5#.

Hence, the soln. is #n=-108/5=-21.6#.

Related questions
See all questions in Equations with Variables on Both Sides
Impact of this question
1644 views around the world
You can reuse this answer
Creative Commons License