How do you solve $-2 + 7x - 3x^2<0$ ?

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Answer 1 · 2015-05-12T10:05:01

The answer is $x in (-oo;1/3)uu(2;+oo)$

$-3x^2+7x-2<0$

$Delta=7^2-4*(-3)*(-2)=25$
$sqrt(Delta)=5$
$x_1=(-7-5)/-6=2$
$x_2=(-7+5)/-6=1/3$
graph{-3x^2+7x-2 [-4.385, 4.386, -2.19, 2.194]}

From the graph you see,that the solution of the inequality is:
$f(x)<0 iff x in (-oo;1/3) uu (2; +oo)$

How do you solve -2 + 7x - 3x^2<0-2 + 7x - 3x^2<0?