# How do you solve 2(x-4)<=2+3(x-6)?

Jan 21, 2017

$x \ge 8$

#### Explanation:

The first step is to distribute the brackets on both sides of the inequality.

$\Rightarrow 2 x - 8 \le 2 + 3 x - 18$

Next, collect terms in x to one side and numeric values on the other side.

subtract 2x from both sides.

$\cancel{2 x} \cancel{- 2 x} - 8 \le 2 + 3 x - 2 x - 18$

$\Rightarrow - 8 \le x - 16$

Isolate x on the right side by adding 16 to both sides.

$- 8 + 16 \le x \cancel{- 16} \cancel{+ 16}$

$\Rightarrow 8 \le x \Rightarrow x \ge 8$