How do you solve #2s-4.2=-8s+8#?

Question

1281 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-04-28T03:44:17

See the entire solution process below:

First, add #color(red)(4.2)# and #color(blue)(8s)# to each side of the equation to isolate the #s# term while keeping the equation balanced:

#color(blue)(8s) + 2s - 4.2 + color(red)(4.2) = color(blue)(8s) - 8s + 8 + color(red)(4.2)#

#(color(blue)(8) + 2)s - 0 = 0 + 12.2#

#10s = 12.2#

Now, divide each side of the equation by #color(red)(10)# to solve for #s# while keeping the equation balanced:

#(10s)/color(red)(10) = 12.2/color(red)(10)#

#(color(red)(cancel(color(black)(10)))s)/cancel(color(red)(10)) = 1.22#

#s = 1.22#