# How do you solve 2x^2-13x+15=0 by factoring?

Oct 11, 2015

(2x-3)(x-5)

#### Explanation:

Split the middle term coefficient -13 so that the product of twp parts is 15*2= 30

13 can thus be split as -3-10, Accordingly,

$2 {x}^{2} - 13 x + 15$

=$2 {x}^{2} - 3 x - 10 x + 15$

=$\left(2 {x}^{2} - 3 x\right) - \left(10 x - 15\right)$

=$x \left(2 x - 3\right) - 5 \left(2 x - 3\right)$

=$\left(2 x - 3\right) \left(x - 5\right)$