How do you solve #2x^2-3<=x#?

2 Answers
Oct 6, 2016

Answer:

X

Explanation:

#2x^2-3<=x#
Think #2x^2-3=x#
#2x^2-x-3=0#
Factorise
#(2x-3)(x+1)=0#
So actually
#(2x-3)(x+1)<=0#
When you do this make sure you keep everything on the right sides
Now sketch the graph. Yes please do that!!
It is bucket shaped and crosses the x axis at #3/2 # and -1
So for the values to be less than or equal to 0, x must be greater than or equal to -1 and less than or equal to #3/2#

#-1<=x<=3/2#

Oct 6, 2016

Answer:

Sorry #-1<=x<=3/2#

Explanation:

See previous answer