# How do you solve #2x^2-7x+3>=0# by graphing?

##### 1 Answer

Feb 22, 2017

#### Answer:

#### Explanation:

Factorise the quadratic and find the roots.

#rArr(2x-1)(x-3)=0#

#rArr"roots are "x=1/2" and " x=3#

#x=0toy=3rArr(0,3)#

#"coefficient of " x^2>0" thus" uu# With this information we can sketch the function.

graph{2x^2-7x+3 [-10, 10, -5, 5]}To solve

#2x^2+7x-3>=0# Consider the region above and including the x-axis.Above x-axis to the left of

#1/2# and right of 3