How do you solve #2x + 4x + 3x=21#?

1 Answer
Aug 3, 2015

I found #7/3#

Explanation:

You can add together all the terms on the left because they have the same litteral part and get:
#9x=21#
you can now transfer the #9# to the right but dividing as:
#x=21/9#
This is because in your Equation the left has always to be equal to the right. If you decide to get rid of the #9# on the left (dividing by #9#) you must do the same on the right:
#(9x)/(color(red)(9))=21/(color(red)(9))#
#(cancel(9)x)/(cancel(9))=21/(color(red)(9))#
now you can divide both by #3#:
#x=(21/3)/(9/3)=7/3#