# How do you solve #2x=sqrt[12x-5]# and find any extraneous solutions?

##### 1 Answer

Nov 9, 2017

#### Answer:

Start by squaring both sides...

#### Explanation:

...giving

...now you can subtract 12x and add 5 to both sides, giving:

...this is a quadratic equation with coefficients 4, -12, and 5.

Remember your forumula, if

...and for coefficients a = 4, b = -12, c = 5, your roots are:

2.5 and 0.5

GOOD LUCK