How do you solve #2x(x-7)(x+4)=0#?

2 Answers

Answer:

#x=-4, 0, 7#

Explanation:

Given cubic equation:

#2x(x-7)(x+4)=0#

#2x=0\ \ or\ \ x-7\ \ or \ \ x+4=0#

#x=0\ \ or\ \ \ x=7\ \ \ or \ \ \ x=-4#

#x=-4, 0, 7#

Jul 22, 2018

Answer:

#x=0#, #x=7# and #x=-4#

Explanation:

Let's set all factors equal to zero:

#2x=0=>x=0#

#x-7=0=>x=7#

#x+4=0=>x=-4#

Therefore, our zeroes are at #x=0#, #x=7# and #x=-4#.

Hope this helps!