# How do you solve # 2x – y = 4#, #3x + y = 1# by graphing and classify the system?

##### 1 Answer

#### Answer:

See a solution process below:

#### Explanation:

For each of the equations we can find two points on the line and then draw a line through the points to graph the line.

**Equation 1**

For

For

graph{(x^2+(y+4)^2-0.05)((x-2)^2+y^2-0.05)(2x-y-4)=0 [-15, 15, -7.5, 7.5]}

**Equation 2**

For

For

graph{(3x+y-1)(x^2+(y-1)^2-0.05)((x-2)^2+(y+5)^2-0.05)(2x-y-4)=0 [-15, 15, -7.5, 7.5]}

**Solution**

We can see the lines cross at

Therefore:

The system is consistent because it has at least one solution. And, it is independent because the lines have different slopes.

graph{(3x+y-1)((x-1)^2+(y+2)^2-0.015)(2x-y-4)=0 [-6, 6, -3, 3]}