# How do you solve 2y-10+18y=10y-3\times 30?

Jun 24, 2018

$y = - 8$

#### Explanation:

$2 y - 10 + 18 y = 10 y - 3 \times 30$

Firstly, we make the multiplication:

$2 y - 10 + 18 y = 10 y - 90$

Secondly, we collect and put all of the similar elements from the one side and the numbers from the other side:

$2 y + 18 y - 10 y = 10 - 90$

$10 y = - 80$

$y = \frac{- 80}{10}$

$y = - 8$

Jun 24, 2018

$y = - 8$

#### Explanation:

We can start by combining our like terms to get

$20 y - 10 = 10 y - 90$

Next, we can add $10$ to both sides to get

$20 y = 10 y - 80$

Remember, we want our constants on one side, and our variables on the other. To do this, we can subtract $10 y$ from both sides.

$10 y = - 80$

Lastly, dividing both sides by $10$ gives us

$y = - 8$

Hope this helps!