How do you solve #2y-10+18y=10y-3\times 30#?

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Answer 1 · 2018-06-24T20:10:50

#y = -8#

#2y - 10 + 18y = 10y - 3 xx 30#

Firstly, we make the multiplication:

#2y - 10 + 18y = 10y - 90#

Secondly, we collect and put all of the similar elements from the one side and the numbers from the other side:

#2y + 18y - 10y = 10 - 90#

#10y = -80#

#y = (-80)/10#

#y = -8#

Answer 2 · 2018-06-24T21:53:22

#y=-8#

We can start by combining our like terms to get

#20y-10=10y-90#

Next, we can add #10# to both sides to get

#20y=10y-80#

Remember, we want our constants on one side, and our variables on the other. To do this, we can subtract #10y# from both sides.

#10y=-80#

Lastly, dividing both sides by #10# gives us

#y=-8#

Hope this helps!