How do you solve #3.1(x+2)-1.5x=5.2(x-4)#? Algebra Linear Equations Equations with Variables on Both Sides 1 Answer EZ as pi Sep 5, 2016 #x = 7.5# Explanation: Treat the decimals the same as normal integers. #3.1x+6.2 -1.5x = 5.2x-20.8 " "larr # multiply out brackets #6.2 +20.8 = 5.2x -3.1x+1.5x" " larr # re-arrange terms #27 = 3.6x# #x = 27/3.6# #x = 7.5# Answer link Related questions How do you check solutions to equations with variables on both sides? How do you solve #125+20w-20w=43+37w-20w#? How do you solve for x in #3(x-1) = 2 (x+3)#? Is there a way to solve for x without using distribution in #4(x-1) = 2 (x+3)#? How do you solve for t in #2/7(t+2/3)=1/5(t-2/3)#? How do you solve #5n + 34 = −2(1 − 7n)#? How do you simplify first and then solve #−(1 + 7x) − 6(−7 − x) = 36#? Why is the solution to this equation #-15y + 7y + 1 = 3 - 8y#, "no solution"? How do you solve for variable w in the equation #v=lwh#? How do you solve #y-y_1=m(x-x_1)# for m? See all questions in Equations with Variables on Both Sides Impact of this question 2166 views around the world You can reuse this answer Creative Commons License