How do you solve #-3[ 2a + 3( 5- 2a ) ] = a - [ 6- 4a ]#?

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Answer 1 · 2017-05-15T07:12:54

#39/7#

QUESTION : #-3[2a+3(5-2a)]=a-[6-4a]#

So

#-3[2a+15-6a]=a-[6-4a]#

Expanding inside the bracket on LHS,

#-3[15-4a] =a-[6-4a]#

Expanding inside the bracket on LHS,

#-45+12a =a-6+4a#

Simplifying on RHS

#-45+12a =5a-6#

#-45+6 =5a-12a#

Seperating numbers and variables,

#-39 =-7a#

# a=(-39)/-7 #

# a=39/7#