How do you solve #3 (2x - 5) = 3 (x + 1)#?

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Answer 1 · 2018-05-14T21:21:58

#x = 6#

First multiply out the brackets.

#6x - 15 = 3x +3#

Rearrange equation to have like terms on the same side.

#6x - 3x = 3+15#
#3x = 18#

Divide by #3# to have #x# on its own.

#(3x)/3 = 18/3#

#x = 6#