Question

How do you solve `3(4x-2)=-2(-6x+3)`?

Answer 1

`x` = any value

Explanation:

multiply out brackets:

`3(4x-2)=12x-6`

`12x-6=-2(-6x+3)`

`-2(-6x+3)=12x-6`

`12x-6=12x-6`

Since both equations are the same, `x` could have any value and still satisfy this system of equations.