How do you solve #3t-2=5(t-2)-2(t-4)#?

1 Answer
Aug 12, 2017

The solution is undecidable.

Explanation:

First multiply out the brackets (parentheses) on the right side:

#3t−2=5(t−2)−2(t−4)=5t-10-2t+8#

Now collect terms including #t# on the left and terms that are just numbers on the right. Remember to change the sign when you move a number from one side to the other:

#3t-5t+2t=2-10+8#

Collect like terms:

#0t=0#

This does not allow us to determine the value of #t#.