Question

How do you solve `3x+11=7x-5`?

Answer 1

Subtract `3x` from both sides
`cancel(3x)-cancel(3x)+11=7x-3x-5`
You get
`11=4x-5`
Add 5 to both sides
`11+5=4x-cancel5+cancel5`
You get
`16=4x`
Divide both sides by 4
`16/4=(4x)/4`
You get
`4=x`