How do you solve #3x + 19 = 3 - 5x#?

2 Answers
Jun 24, 2018

#x=-2#

Explanation:

#3x+19=3-5x#

#:.3x+5x=3-19#

#:.8x=-16#

#:.x=-16/8#

#:.x=-2#

~~~~~~~~~

check:-

substitute #x=-2#

#:.3(-2)+19=3-5(-2)#

#:.-6+19=3+10#

#:.13=13#

Jun 24, 2018

#x=-2#

Explanation:

Given: #3x+19=3-5x#

To end up with all the #x# terms on the left sides add #color(red)(5x)# to both sides.

#color(green)(3x+19 = 3-5x color(white)("dddd") ->color(white)("dddd")ubrace(3xcolor(red)(+5x))color(white)("d") +19 = 3color(white)("d") ubrace(-5x color(red)(+5x)) )#
#color(white)("ddddddddddddddddddddddddd.d") darrcolor(white)("dddddddddddddd") darr#
#color(green)(color(white)("dddddddddddddddddd") ->color(white)("dddddd") 8xcolor(white)("ddd") +19 =3color(white)("...") +0)#

Subtract 19 from both sides #->color(white)("ddd") 8x =-16#

Divide both sides by #color(red)(8)#

#color(green)(8x=-16 color(white)("dddddddddd") ->color(white)("ddddd") 8/color(red)(8) x=-16/color(red)(8))#

But #8/8=1 and 1xx x = x#

#color(green)(color(white)("ddddddddddddddddddd") ->color(white)("dddddd") x=-2)#