How do you solve #3x^2+24x>=-41# by graphing?

1 Answer
Jan 1, 2017

Answer:

x-axis with the gap #(-4-sqrt(7/3), -4+sqrt(7/3))#. See this gap in the graph.

Explanation:

#x^2+24x=3(x+4)^2-48>=-41 to x >=-4+sqrt(7/3) and x<=-4-sqrt(7/3)#

The 2-D graph is for {(x, y)}, satisfying #3x^2+24x>=-41#.

The x-axis sans the gap

#(-4-sqrt(7/3), -4+sqrt(7/3))=(-5.5275, -2.4725)# is 1-D solution ,

In 3-D, the gap is cylindrical, about the x-axis..

graph{3x^2+24x+41>=0 [-10, 10, -5, 5]}