How do you solve #3x^2+5x-2=0# by factoring?

1 Answer
May 24, 2018

Answer:

x1=-4/6 and x2=-1

Explanation:

we need the mathematical formula #B^2-4AS# . B is our 5 its the one that has the x but not in any form of power so we want our x not to be an exponential. The A is our 3 which is the one that is exponential. And our S is the standard number which is -2 in this case. So by using the formula we have : #5^2-4*3*-2=1#
Now we are going to use another the next part of the mathematical formula #-5+sqrt1=Q =>Q/6# and our next formula for the second solution #-5-sqrt1=N=>N/6#
So our answers are #x1=-4/6# and #x2=-1#
with x1 and x2 being the solutions.