# How do you solve 3x^2+5x-2=0 by factoring?

May 24, 2018

we need the mathematical formula ${B}^{2} - 4 A S$ . B is our 5 its the one that has the x but not in any form of power so we want our x not to be an exponential. The A is our 3 which is the one that is exponential. And our S is the standard number which is -2 in this case. So by using the formula we have : ${5}^{2} - 4 \cdot 3 \cdot - 2 = 1$
Now we are going to use another the next part of the mathematical formula $- 5 + \sqrt{1} = Q \implies \frac{Q}{6}$ and our next formula for the second solution $- 5 - \sqrt{1} = N \implies \frac{N}{6}$
So our answers are $x 1 = - \frac{4}{6}$ and $x 2 = - 1$