# How do you solve -3x-2y=0 and 3x-y=18 by graphing?

May 18, 2018

From the graphs, the intersection points are $\left(4 , - 6\right)$, so the answer is $x = 4$ and $y = - 6$

#### Explanation:

standard linear equation is $y = m x + b$ format.

$- 3 x - 2 y = 0$

$- 2 y = 0 + 3 x$

y=-3/2x" " -> " equation 1 " [color(red)("Red Graph")]

$3 x - y = 18$

$- y = 18 - 3 x$

$y = - 18 + 3 x$

y=3x-18" " -> " equation 2 " [color(blue)("Blue Graph")]

Now, draw a graph of these linear equations and the intersection of these two graphs is the $\left(x , y\right)$ point that satisfies both these equations.

From the graphs, the intersection points are $\left(4 , - 6\right)$, so the answer is $x = 4$ and $y = - 6$

$- 3 \left(4\right) - 2 \left(- 16\right) = - 12 + 12 = 0$
$3 \left(4\right) - \left(- 6\right) = 12 + 6 = 18$