Question

How do you solve `3x - 3= 8- 2( x + 3)`?

Answer 1

Work backwards PESADM to find the lost unknown.

Explanation:

To find something that is lost it usually best to work backwards.
The order of operation is PEMDAS backwards PESADM.

Think about it this way if you lose something in PE you are a SAD M(an, am)

First it necessary to remove parenthesis and exponents. (PE)
Then either add or subtract doing the opposite (SA)
Then either divide or multiply doing the opposite ( DM)

In this equation start by removing the parenthesis on the left.

`3x -3 = 8 - 2( x +3) = 3x -3 = 8 -2x -6`

Now combine the constants by adding 3 to both sides and using the associative property

`3x -3 +3 = 8 +3 -6 -2x` This results in

`3x = 5 - 2x` Now add 2x to both sides

`3x + 2x = 5 -2x + 2x` this leaves

`5x = 5` last divide both sides by 5

`5x/5 = 5/5` this gives the answer

`x = 1`