# How do you solve 3x-7>5?

May 14, 2018

$x > 4$

#### Explanation:

Solving inequalities is similar to solving equations.

First, we want to add $\textcolor{b l u e}{7}$ to both sides of the inequality:
$3 x - 7 \quad \textcolor{b l u e}{+ \quad 7} > 5 \quad \textcolor{b l u e}{+ \quad 7}$

$3 x > 12$

Now divide both sides by $\textcolor{b l u e}{3}$:
$\frac{3 x}{\textcolor{b l u e}{3}} > \frac{12}{\textcolor{b l u e}{3}}$

$x > 4$

This is the same thing as "$x$ is greater than $4$".

Hope this helps!

May 14, 2018

$x > 4$

#### Explanation:

$3 x - 7 > 5$

Let's make it look simpler by isolating the x-base value.

We can add 7 on both sides to eliminate 7 on LHS

$3 x - 7 + 7 > 5 + 7$
$\mathmr{and} , 3 x > 12$

Dividing both side by 3:

$\mathmr{and} , \frac{3 x}{3} > \frac{12}{3}$
$\mathmr{and} , x > 4$