How do you solve #3y ( 4y - 1) - 2y ( 6y - 5) = 9y - 8( 3+ y )#?

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Answer 1 · 2017-01-03T22:31:50

#y = -4#

First distribute everything:

#12y^2-3y-12y^2 + 10y = 9y-24-8y#

Then combine like terms:

#7y = y-24 -># the two #12y^2# terms cancel out

You can then subtract #y# from both sides:

#6y = -24#

Then divide both sides by #-14# to get that

#y = (-24)/6 = -4#