# How do you solve  4(2x-5)=4(3x-4)?

Jul 6, 2016

$x = - 1$

#### Explanation:

$4 \left(2 x - 5\right) = 4 \left(3 x - 4\right)$

First thing we can do is divide out a four from each side.

$\frac{\cancel{4} \left(2 x - 5\right)}{\cancel{4}} = \frac{\cancel{4} \left(3 x - 4\right)}{\cancel{4}}$

Now that we've gotten rid of our fours, there is no multiplying we have to do. We can just get all variable terms and constants on different sides (isolate the variable).

$2 x - 5 = 3 x - 4$

Add $4$ to both sides and subtract $2 x$ from both sides.

$- 1 = x$

Our final solution: $x = - 1$