How do you solve #4(-8x+5)=-32x-26#?

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Answer 1 · 2017-02-20T14:35:47

See the entire solution process below:

First, expand the terms within parenthesis on the left side of the equation:

#(4 xx -8x) + (4 xx 5) = -32x - 26#

#-32x + 20 = -32x - 26#

Now, add #color(red)(32x)# to each side of the equation:

#color(red)(32x) - 32x + 20 = color(red)(32x) - 32x - 26#

#0 + 20 = 0 - 26#

#20 != -26#

Therefore there is no solution to this problem other than the null or empty set or #x = {O/}#