How do you solve #4(x+3)=5(x-2)#?

2 Answers
Feb 21, 2016

#x=22#

Explanation:

#color(blue)(4(x+3)=5(x-2)#

Use distributive property #color(green)(a(b+c)=ab+ac#

#rarr4x+12=5x-10#

Add #10# to both sides

#rarr4x+12+10=5x-10+10#

#rarr4x+22=5x#

Subtract #4x# both sides

#rarr4x+22-4x=5x-4x#

#rarr22=x#

Check

#color(brown)(4(22+3)=5(22-2)#

#color(brown)(4(25)=5(20)#

#color(brown)(100=100#

It's correct!!! =)

Aug 4, 2018

#x=22#

Explanation:

We can use the distributive property to simplify the left and right sides respectively to get

#4x+12=5x-10#

Next, we can add #10# to both sides to get

#4x+22=5x#, which is the same as

#5x=4x+22#

Lastly, we can subtract #4x# from both sides to get

#x=22#

Hope this helps!