Question

How do you solve `4h+12=11-39h`?

Answer 1

`h=-1/43`

Explanation:

`4h+39h+12=11\stackrel{\cancel(+39h)}{\cancel(-39h)}`
`43h\stackrel{\cancel(-12)}{\cancel(+12)}=11-12`
`43h=-1`
`(\cancel(43)h)/(\cancel(43))=-1/43`

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`h=-1/43`